Originally Posted by

**Ola** Hi,

Very grateful for your help, pls can you help me to have a look at the solutions I finally arrived at just to be sure I am on the right track:

(i)

P=Po(1-e^-0.05(5))

P = 10,000(1-^-0.25)

P = 10000 (1-0.7788)

P = 10,000(0.2212)

P = 2,212

(ii)

1/2 of 10,000 (1-e^0.05(T))

= 1/2(10,000) (1 - 0.95123T)

= 5,000 (1 - 0.95123T

= 5,000 - 4756.15T

4756.15T = 5,000

T = 5,000/4756.15

T = 1.05127

T = 1 day (aproximately) **<<<<< if you have 2000 infections in 5 days it would take a little bit longer to have 5000 infections**

(iii)

95% of 10,000 (1 - e^0.05(T))

= 9,500 (1 - 0.95123T)

= 9,500 - 9,036.68T

9036.68T = 9,500

T = 9,500/9036.68

T = 1.051271 day

T = 1 day (aproximately) **<<<<<<< No**