I know that . At the end of the fall there is no more potential energy so all I need is .Each second, 1250 m3 of water passes over a waterfall 115 m high. Three-fourths of the kinetic energy gained by the water in falling is transferred to electrical energy by a hydroelectric generator. At what rate does the generator produce electrical energy? (The mass of 1 m3 of water is 1000 kg.)
To get v I used .
So the final equation is .
I plugged in the numbers and got 1056562500W. According to loncapa (online system) this is wrong. Can anyone see something I did incorrectly?