Q) Find the remainder of 37^47^57 divided by 16?
Any help will be appreciated?
I think I've solved it . . .
SinceFind the remainder of divided by 16
. . we have: .
Now consider consecutive powers-of-5 (mod 16):
The remainders step through a 4-step cycle: .
Now we must determine: .
We have: .
And: . has remainder 13.
But someone check my reasoning and work ... please!