Use cross product to find the sine of the angle between the vectors u (2,3,-6) v(2,3,6)
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Originally Posted by daphnewoon Use cross product to find the sine of the angle between the vectors u (2,3,-6) v(2,3,6) Use the definition of the cross product: Solve for
Hello, thanks for replying I know the formula to solve this question, just that i've gt this equation: (36 , -30, 0) = 10 sin alpha How am i going to manipulate this?
Originally Posted by daphnewoon Hello, thanks for replying I know the formula to solve this question, just that i've gt this equation: (36 , -30, 0) = 10 sin alpha How am i going to manipulate this? I'm not sure how you got this result ... Use the formula I posted in my previous answer: Plug in all the values you know: ... and now solve for
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