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Math Help - very hard question

  1. #1
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    very hard question

    hi this is m question:

    2X 81^\frac{1}{4}
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  2. #2
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    Quote Originally Posted by andyboy179 View Post
    hi this is m question:

    2x 81^\frac{1}{4}
    hint : 3^4=81
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  3. #3
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    dunno, how would i do it?
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  4. #4
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    Quote Originally Posted by andyboy179 View Post
    dunno, how would i do it?
     <br />
2\times (3^4)^{\frac{1}{4}}<br />
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  5. #5
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    i don't understand!!!!!!!!!!!

    this is a question which i have done:
    3X 125^\frac{1}{3} = cube root 125= 5x3=15

    i need to set it out like this for the question i posted, do you know how to work it out like this?
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  6. #6
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    Quote Originally Posted by andyboy179 View Post
    i don't understand!!!!!!!!!!!

    this is a question which i have done:
    3X 125^\frac{1}{3} = cube root 125= 5x3=15

    i need to set it out like this for the question i posted, do you know how to work it out like this?
    5\times 5\times 5=5^3=125 , therefore , \sqrt[3]{125}=5

    so in your case now ,

    3\times 3\times 3\times 3=3^4=81 , therefore , \sqrt[4]{81}=3

    Then proceed , 2\times 3 =6
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  7. #7
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    Quote Originally Posted by mathaddict View Post
    5\times 5\times 5=5^3=125 , therefore , \sqrt[3]{125}=5

    so in your case now ,

    3\times 3\times 3\times 3=3^4=81 , therefore , \sqrt[4]{81}=3

    Then proceed , 2\times 3 =6

    thankyou very much for all the question you have helped me on
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  8. #8
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    Quote Originally Posted by andyboy179 View Post
    thankyou very much for all the question you have helped me on
    you are welcome .
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