hi this is m question:

2X$\displaystyle 81^\frac{1}{4}$

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- Oct 22nd 2009, 08:06 AMandyboy179very hard question
hi this is m question:

2X$\displaystyle 81^\frac{1}{4}$ - Oct 22nd 2009, 08:08 AMmathaddict
- Oct 22nd 2009, 08:11 AMandyboy179
dunno, how would i do it?

- Oct 22nd 2009, 08:14 AMmathaddict
- Oct 22nd 2009, 08:19 AMandyboy179
i don't understand!!!!!!!!!!!

this is a question which i have done:

3X$\displaystyle 125^\frac{1}{3}$ = cube root 125= 5x3=15

i need to set it out like this for the question i posted, do you know how to work it out like this? - Oct 22nd 2009, 08:29 AMmathaddict
- Oct 22nd 2009, 08:33 AMandyboy179
- Oct 22nd 2009, 08:35 AMmathaddict