simplify

**andyboy179** · October 22nd 2009, 06:18 AM

this is my question:

-3----4
2a X 3a=?
----------------------7
would the answer be, 5a

the --- are there because i can't get the numbers to stay above other numbers without there being anything else there.

**mathaddict** · October 22nd 2009, 06:27 AM

Originally Posted by andyboy179

this is my question:

-3----4
2a X 3a=?
----------------------7
would the answer be, 5a

the --- are there because i can't get the numbers to stay above other numbers without there being anything else there.

HI

i think you need to revise your post . If you want to write a fraction ,

\frac{numerator}{denomintator} , then wrap it up with the math tags .

**andyboy179** · October 22nd 2009, 06:28 AM

its not a fraction

**andyboy179** · October 22nd 2009, 06:30 AM

**mathaddict** · October 22nd 2009, 06:35 AM

Originally Posted by andyboy179

$Click image for larger version. Name: untitled.jpg Views: 11 Size: 22.7 KB ID: 13475$

nope , it should be $6A^7$ , 2x3=6 ..

btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags .

**andyboy179** · October 22nd 2009, 06:40 AM

Originally Posted by mathaddict

nope , it should be $6A^7$ , 2x3=6 ..

btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags .

thanks, $3^4\times 3^- 2\times 3^7$

**mathaddict** · October 22nd 2009, 06:45 AM

Originally Posted by andyboy179

thanks, $3^4\times 3^- 2\times 3^7$

3^{-2} for the term in the middle .

**andyboy179** · October 22nd 2009, 06:47 AM

Originally Posted by mathaddict

3^{-2} for the term in the middle .

kk, would the answer to that be $3^9$

**mathaddict** · October 22nd 2009, 06:49 AM

Originally Posted by andyboy179

kk, would the answer to that be $3^9$

yup , $3^9$

**andyboy179** · October 22nd 2009, 06:50 AM

Originally Posted by mathaddict

yup , $3^9$

thanks

**andyboy179** · October 22nd 2009, 06:52 AM

$2a^3 b\times 3ab^- 3$ would it = $6a^4 b^4$

**Amer** · October 22nd 2009, 06:57 AM

Originally Posted by andyboy179

$2a^3 b\times 3ab^- 3$ would it = $6a^4 b^4$

you answer is wrong

$2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$

**andyboy179** · October 22nd 2009, 07:02 AM

Originally Posted by Amer

you answer is wrong

$2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$

sorry its not -3 its just 3 sorry

**Amer** · October 22nd 2009, 07:40 AM

Originally Posted by andyboy179

sorry its not -3 its just 3 sorry

in this case your solution is correct

Thread: simplify

LinkBack

Thread Tools

Display

simplify

Similar Math Help Forum Discussions

simplify #2

Please simplify

Can you simplify this further?

Simplify

Search Tags