this is my question: -3----4 2a X 3a=? ----------------------7 would the answer be, 5a the --- are there because i can't get the numbers to stay above other numbers without there being anything else there.
Follow Math Help Forum on Facebook and Google+
Originally Posted by andyboy179 this is my question: -3----4 2a X 3a=? ----------------------7 would the answer be, 5a the --- are there because i can't get the numbers to stay above other numbers without there being anything else there. HI i think you need to revise your post . If you want to write a fraction , \frac{numerator}{denomintator} , then wrap it up with the math tags .
its not a fraction
Originally Posted by andyboy179 nope , it should be $\displaystyle 6A^7$ , 2x3=6 .. btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags .
Originally Posted by mathaddict nope , it should be $\displaystyle 6A^7$ , 2x3=6 .. btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags . thanks, $\displaystyle 3^4\times 3^- 2\times 3^7$
Originally Posted by andyboy179 thanks, $\displaystyle 3^4\times 3^- 2\times 3^7$ 3^{-2} for the term in the middle .
Originally Posted by mathaddict 3^{-2} for the term in the middle . kk, would the answer to that be $\displaystyle 3^9$
Originally Posted by andyboy179 kk, would the answer to that be $\displaystyle 3^9$ yup , $\displaystyle 3^9$
Originally Posted by mathaddict yup , $\displaystyle 3^9$ thanks
$\displaystyle 2a^3 b\times 3ab^- 3$ would it = $\displaystyle 6a^4 b^4$
Originally Posted by andyboy179 $\displaystyle 2a^3 b\times 3ab^- 3$ would it = $\displaystyle 6a^4 b^4$ you answer is wrong $\displaystyle 2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$
Originally Posted by Amer you answer is wrong $\displaystyle 2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$ sorry its not -3 its just 3 sorry
Originally Posted by andyboy179 sorry its not -3 its just 3 sorry in this case your solution is correct
View Tag Cloud