1. ## simplify

this is my question:

-3----4
2a X 3a=?
----------------------7
would the answer be, 5a

the --- are there because i can't get the numbers to stay above other numbers without there being anything else there.

2. Originally Posted by andyboy179
this is my question:

-3----4
2a X 3a=?
----------------------7
would the answer be, 5a

the --- are there because i can't get the numbers to stay above other numbers without there being anything else there.
HI

i think you need to revise your post . If you want to write a fraction ,

\frac{numerator}{denomintator} , then wrap it up with the math tags .

3. its not a fraction

4. Originally Posted by andyboy179
nope , it should be $6A^7$ , 2x3=6 ..

btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags .

5. Originally Posted by mathaddict
nope , it should be $6A^7$ , 2x3=6 ..

btw , to write in latex , 2A^3\times 3A^4 , then wrap with the tags .

thanks, $3^4\times 3^- 2\times 3^7$

6. Originally Posted by andyboy179
thanks, $3^4\times 3^- 2\times 3^7$
3^{-2} for the term in the middle .

7. Originally Posted by mathaddict
3^{-2} for the term in the middle .

kk, would the answer to that be $3^9$

8. Originally Posted by andyboy179
kk, would the answer to that be $3^9$
yup , $3^9$

9. Originally Posted by mathaddict
yup , $3^9$

thanks

10. $2a^3 b\times 3ab^- 3$ would it = $6a^4 b^4$

11. Originally Posted by andyboy179
$2a^3 b\times 3ab^- 3$ would it = $6a^4 b^4$
you answer is wrong

$2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$

12. Originally Posted by Amer
you answer is wrong

$2a^3b\times 3ab^{-3} = (2\times 3) a^{3+1} b^{1-3} =6a^4b^{-2}$
sorry its not -3 its just 3 sorry

13. Originally Posted by andyboy179
sorry its not -3 its just 3 sorry
in this case your solution is correct