How do I determine a vector equation of a line..?
with the same x-intercept as [x,y,z]=[3,3,0]+t[3,-5,-9] and the same z-intercept as [x,y,z]=[6,-2,-3]+t[3,-1,-2]
Thanks a lot (: !
How do I determine a vector equation of a line..?
with the same x-intercept as [x,y,z]=[3,3,0]+t[3,-5,-9] and the same z-intercept as [x,y,z]=[6,-2,-3]+t[3,-1,-2]
Thanks a lot (: !
Hello bebejay
Welcome to Math Help Forum!The -intercept on the second line is where it meets the -axis; i.e. . This is where : the point whose position vector is .
But I'm afraid I don't understand what you mean by the -intercept for the first line. This line doesn't intersect the -axis. (When .)
Are you sure you have the correct information here?
Grandad