How do I determine a vector equation of a line..?
with the same x-intercept as [x,y,z]=[3,3,0]+t[3,-5,-9] and the same z-intercept as [x,y,z]=[6,-2,-3]+t[3,-1,-2]
Thanks a lot (: !
How do I determine a vector equation of a line..?
with the same x-intercept as [x,y,z]=[3,3,0]+t[3,-5,-9] and the same z-intercept as [x,y,z]=[6,-2,-3]+t[3,-1,-2]
Thanks a lot (: !
Hello bebejay
Welcome to Math Help Forum!The $\displaystyle z$-intercept on the second line is where it meets the $\displaystyle z$-axis; i.e. $\displaystyle x = y = 0$. This is where $\displaystyle t = -2$: the point whose position vector is $\displaystyle \begin{pmatrix}0\\0\\1\end{pmatrix}$.
But I'm afraid I don't understand what you mean by the $\displaystyle x$-intercept for the first line. This line doesn't intersect the $\displaystyle x$-axis. (When $\displaystyle t=0, z=0, y\ne0$.)
Are you sure you have the correct information here?
Grandad