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Math Help - Resolving Vector Components

  1. #1
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    Cool Resolving Vector Components

    Hi, I need help with resolving components of vector forces.

    For example how would you solve the last question mentioned on this website

    Code:
    http://www.s-cool.co.uk/alevel/physics/vectors-and-scalars-and-linear-motion/resolving-vectors-into-components.html
    I've read the procedure on the above page but still confused on how to solve such questions.

    Besides the above question I'm having difficulty with the following:

    Firstly I can't figure out how to draw the components.

    Secondly, once I have drawn the components I can't figure out which component/force should be Fsintheta and which one should be Fcostheta.

    Please provide details on how to do the above.

    Thanks!
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  2. #2
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    S-Cool | Resolving Vectors into Components

    OP wants help w/ the last question.
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  3. #3
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    huh?
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  4. #4
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    Quote Originally Posted by unstopabl3 View Post
    huh?
    I made your reference into a link that is "clickable" ...
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    I thought direct links are not allowed thus I coded mine. Thanks though, I just need someone to help me now
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    Quote Originally Posted by unstopabl3 View Post
    Hi, I need help with resolving components of vector forces.

    For example how would you solve the last question mentioned on this website

    Code:
    http://www.s-cool.co.uk/alevel/physics/vectors-and-scalars-and-linear-motion/resolving-vectors-into-components.html
    I've read the procedure on the above page but still confused on how to solve such questions.

    Besides the above question I'm having difficulty with the following:

    Firstly I can't figure out how to draw the components.

    Secondly, once I have drawn the components I can't figure out which component/force should be Fsintheta and which one should be Fcostheta.

    Please provide details on how to do the above.

    Thanks!
    It doesn't matter in this example because cos(45) = sin(45) = \frac{\sqrt2}{2}
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  7. #7
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    Yea I figured, but how would you go on about solving it?

    Also can you answer my other questions.

    Thanks.
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  8. #8
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    Quote Originally Posted by unstopabl3 View Post
    Yea I figured, but how would you go on about solving it?

    Also can you answer my other questions.

    Thanks.
    I resolved the force of the wind to find it's vertical component which I get to be F_v = -300sin(45) = -150\sqrt2

    This would give a resultant force of 1000-(500+150\sqrt2) but the site says that is wrong and I've no idea how they got their answer
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  9. #9
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    Thanks, could you tell me step by step on how to resolve components in such questions?

    Thanks.
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  10. #10
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    resultant's x-component, R_x = 300\cos(45)

    resultant's y-component, R_y = 500-1000-300\sin(45)

    |R| = \sqrt{R_x^2 + R_y^2} \approx 357.6 Newtons
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  11. #11
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    Could you please explain to me (with diagrams if possible) as how you got those components for that question.

    Thanks!
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  12. #12
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    Quote Originally Posted by skeeter View Post
    resultant's x-component, R_x = 300\cos(45)

    resultant's y-component, R_y = 500-1000-300\sin(45)

    |R| = \sqrt{R_x^2 + R_y^2} \approx 357.6 Newtons
    HI

    shouldn't Rx be 300 sin 45 ?

    and the component in Ry = 300 cos 45 ?
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  13. #13
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    Quote Originally Posted by unstopabl3 View Post
    Could you please explain to me (with diagrams if possible) as how you got those components for that question.

    Thanks!
    HI

    you can draw a triangle with 300 being the hypothenus and 45 degree being the angle on top . Its just exactly the same in the animation and you just add an extra line at the bottom .

    Then use some basic trigo to get them .
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  14. #14
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    That's how did it and got the answer right just wanted to make sure because I got confused with "skeeter's" last post, where I thought he may have made a mistake with the X and Y components. I guess you think same as well. The answer came same either ways because the angle value is same for cos and sin


    Besides the above question I'm having difficulty with the following:

    Firstly I can't figure out how to draw the components.

    Secondly, once I have drawn the components I can't figure out which component/force should be Fsintheta and which one should be Fcostheta.

    Please provide details on how to do the above.

    Thanks.
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  15. #15
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    Quote Originally Posted by unstopabl3 View Post
    That's how did it and got the answer right just wanted to make sure because I got confused with "skeeter's" last post, where I thought he may have made a mistake with the X and Y components. I guess you think same as well. The answer came same either ways because the angle value is same for cos and sin


    Besides the above question I'm having difficulty with the following:

    Firstly I can't figure out how to draw the components.

    Secondly, once I have drawn the components I can't figure out which component/force should be Fsintheta and which one should be Fcostheta.

    Please provide details on how to do the above.

    Thanks.
    Vector Resolution

    Try reading that . It might help .

    Or see the diagram i attached . Sorry for the unclear image though .

    You will see a triangle with F being the hypothenus , Fx and Fy are respectively 2 sides of the triangle .

    So if you want resolve horizontally, Fx , you need a trigonometric ratio to relate Fx and F . So in this case , you will use

    cos theta = Fx / F

    so Fx = F cos theta .

    Same goes to resolving vertically , find a trigonometric ratio which would relate Fy and F .

    So would it be sin ?
    Attached Thumbnails Attached Thumbnails Resolving Vector Components-untitled.bmp  
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