Here is the question...
You are riding in an elevator. Starting from rest, the elevator undergoes the following motions:
- It accelerates from rest (v=0.0 m/s) upwards for 5.0 at +2.0m/sē.
- It then coasts for 20.0 s at 10.0 m/s (a=0.0 m/sē).
- Finally, starting at 10.0 m/s, it accelerates downward for 2.5 s at -4.00 m/sē
Complete a position-time graph, a velocity-time graph, and an acceleration time graph.
First, I completed a velocity-time graph, which looked something like this.
But I don't exactly know how to make the position-time or the acceleration-time. Can someone explain how? Do I need a formula that finds distance using acceleration and time (for the position time graph)?
Any help would be appreciated. Thanks!