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Math Help - Mechanics

  1. #1
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    Mechanics

    Hi i am revising, exams in 2 week and i got stuck on this question

    A light inextensible string hsa its e4nds attached to 2 fixed points A and B.... With A vertically above B, smooth ring, R of mass 0.8Kg is treaded on the string and is pulled by a horizontal force of magnitude x newton...The ring rests in equilibrium...



    Find tension in the string <<< What am i suppsed to find, what tension exactly ?

    Value of X

    I can work the triangles

    by vectors, or trigonometry, i just dont know what to look for ?
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  2. #2
    MHF Contributor
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    Hello ramzel
    Quote Originally Posted by ramzel View Post
    Hi i am revising, exams in 2 week and i got stuck on this question

    A light inextensible string hsa its e4nds attached to 2 fixed points A and B.... With A vertically above B, smooth ring, R of mass 0.8Kg is treaded on the string and is pulled by a horizontal force of magnitude x newton...The ring rests in equilibrium...



    Find tension in the string <<< What am i suppsed to find, what tension exactly ?

    Value of X

    I can work the triangles

    by vectors, or trigonometry, i just dont know what to look for ?
    I take it that the 50* and 20* in your diagram are the angles that the two sections of the string make with the horizontal.

    The tension in the string is the same on either side of the ring, and acts upon the ring in a direction along each section of the string. So the ring is in equilibrium under the action of four forces:

    1. its weight vertically downwards
    2. the force X horizontally
    3. a tension, T say, inclined at an angle 50^o above the horizontal
    4. a tension T inclined at an angle 20^o below the horizontal

    Resolve vertically, and you can find T directly without needing to involve X.

    Grandad
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  3. #3
    Junior Member
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    So the force acting on these 2 string on the left have the same force ? well i could just resolve the vertical part and equate it to be 8N ?


    Thank you grandpa got the answer simple to work out :/ they could have simply asked, what the force acting on the string:/
    Last edited by ramzel; October 9th 2009 at 05:28 AM.
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