how do you solve 9^x = 27 thanks for any feedback
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Originally Posted by charmifs how do you solve 9^x = 27 thanks for any feedback I would suggest that you take a logarithm of both sides. Remember that So proceed like so:
Originally Posted by charmifs how do you solve 9^x = 27 thanks for any feedback Another way is to use the powers of 3: If the bases are equal so too must the exponents:
Thanks. That really helped.
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