1. ## fractional indices

how do you solve

9^x = 27

thanks for any feedback

2. Originally Posted by charmifs
how do you solve

9^x = 27

thanks for any feedback
I would suggest that you take a logarithm of both sides.

Remember that $\log_a (a^b) = b$

So proceed like so:

$\log_9 (9^x) = \log_9 (27)$

3. Originally Posted by charmifs
how do you solve

9^x = 27

thanks for any feedback
Another way is to use the powers of 3:

$(3^2)^x = 3^{2x} = 3^3$

If the bases are equal so too must the exponents:

$2x = 3$

4. Thanks. That really helped.