I need to solve for V in this equation but every answer seem to be wrong, please help... Original equation: d= Vt + 1/2 a t^2
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$\displaystyle d=vt+\frac{1}{2}at^2$ $\displaystyle d-\frac{1}{2}at^2=vt$ $\displaystyle \frac{d-\frac{1}{2}at^2}{t}=v$
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