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Thread: solving for a different variable

  1. September 29th 2009, 07:03 PM #1
    runner940
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    solving for a different variable

    I need to solve for V in this equation but every answer seem to be wrong, please help...

    Original equation: d= Vt + 1/2 a t^2
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  2. September 29th 2009, 08:15 PM #2
    iamanoobatmath
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    d=vt+\frac{1}{2}at^2

    d-\frac{1}{2}at^2=vt

    \frac{d-\frac{1}{2}at^2}{t}=v
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