# solving for a different variable

• September 29th 2009, 07:03 PM
runner940
solving for a different variable
I need to solve for V in this equation but every answer seem to be wrong, please help...

Original equation: d= Vt + 1/2 a t^2
• September 29th 2009, 08:15 PM
iamanoobatmath
$d=vt+\frac{1}{2}at^2$

$d-\frac{1}{2}at^2=vt$

$\frac{d-\frac{1}{2}at^2}{t}=v$