I need to solve for V in this equation but every answer seem to be wrong, please help...

Original equation: d= Vt + 1/2 a t^2

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- Sep 29th 2009, 07:03 PMrunner940solving for a different variable
I need to solve for V in this equation but every answer seem to be wrong, please help...

Original equation: d= Vt + 1/2 a t^2 - Sep 29th 2009, 08:15 PMiamanoobatmath
$\displaystyle d=vt+\frac{1}{2}at^2$

$\displaystyle d-\frac{1}{2}at^2=vt$

$\displaystyle \frac{d-\frac{1}{2}at^2}{t}=v$