When a satellite is a distance R from the center of Earth, the force due to gravity on the satellite is F. What is the force due to gravity on the satellite when its distance from the center of Earth is 3R?
(1) F/9 (3) F
(2) F/3 (4) 9F
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When a satellite is a distance R from the center of Earth, the force due to gravity on the satellite is F. What is the force due to gravity on the satellite when its distance from the center of Earth is 3R?
(1) F/9 (3) F
(2) F/3 (4) 9F
You should know that at the level you are working gravity acts viaQuote:
Originally Posted by symmetry
an inverse square law. So:
F(kx)/F(x)=1/k^2,
In you case k=3, so F(3R)=F(R)/9.
So the answer is (1).
RonL
Thanks! I did not know that formula.
The question obviously presupposes that you know that gravity actsQuote:
Originally Posted by symmetry
via an inverse square law. The relation:
F(kx)/F(x)=1/k^2,
is an imeadiate consequence of the inverse square law.
RonL