Two cars are approaching an intersection. One is 2 miles south of the intersection and is moving at a constant speed of 30 mph. At the same time, the other car is 3 miles east of the intersection and is moving at a constant speed of 40 mph. Express the distance d between the cars as a function of time t.
Like always, your replies are greatly appreciated as I study for my test.
We have D = r*t
Originally Posted by symmetry
Distance of the slow car moving at 30 mph is 30t
Distance of the fast car moving at 40 mph is 40t
Now, this problem is practically asking you to use the pythag. theorem.
a^2 + b^2 = c^2
= sqrt(40t^2 + 30t^2)
= sqrt(1600t^2 + 900t^2)
= 50*t, which is your final answer.