A bullet of mass 0.205 kg traveling horizontally at a speed of 250 m/s embeds itself in a block of mass 3.5 kg that is sitting at rest on a nearly frictionless surface.
What is the speed of the block after the bullet embeds itself in the block?
A bullet of mass 0.205 kg traveling horizontally at a speed of 250 m/s embeds itself in a block of mass 3.5 kg that is sitting at rest on a nearly frictionless surface.
What is the speed of the block after the bullet embeds itself in the block?
$\displaystyle m_1 v_{1i} + m_2 v_{2i} = m_1 v_{1f} + m_2 v_{2f} $
$\displaystyle m_1 v_{1i} + 0 = 0 + m_2 v_{2f}$
(0.205 kg) (250m/s) = (3.5kg) $\displaystyle (v_{2f})$
$\displaystyle v_{2f} = 14.643 $