Results 1 to 3 of 3

Math Help - Story problem

  1. #1
    Junior Member
    Joined
    Nov 2006
    From
    California
    Posts
    36

    Story problem

    A Company specializing in magazine sales over the telephone found that the 2500 phone calls , 360 resulted in sales and were made by male callers, and 480 resulted in sales were made by female callers,If the compnay gets twice as many saler per call with a women's voice then with a man's voice, then how many of the 3500 calls were made by females,

    Help please I'm coming up with 1,000 is that right?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by fancyface View Post
    A Company specializing in magazine sales over the telephone found that the 2500 phone calls , 360 resulted in sales and were made by male callers, and 480 resulted in sales were made by female callers,If the compnay gets twice as many saler per call with a women's voice then with a man's voice, then how many of the 3500 calls were made by females,

    Help please I'm coming up with 1,000 is that right?
    Suppose the fraction of sales for male callers is k, then the fraction for
    femail callers is 2k.

    If there were m callers with male voices and f callers with femail voices, then:

    km=360,

    and:

    2kf=480.

    Also:

    m+f=2500 (or 3500, you will have to sort out which this is yourself),

    so:

    km+kf=360+240=k 2500.

    so:

    k=600/2500=0.24, and

    so:

    2x0.24xf=480,

    which gives:

    f=1000.

    RonL
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    Quote Originally Posted by fancyface View Post
    A Company specializing in magazine sales over the telephone found that the 2500 phone calls , 360 resulted in sales and were made by male callers, and 480 resulted in sales were made by female callers,If the compnay gets twice as many saler per call with a women's voice then with a man's voice, then how many of the 3500 calls were made by females,

    Help please I'm coming up with 1,000 is that right?

    Let us see. Here is one way.

    We are asked to find how many of the 2500 (I assume the 3500 is a typo) callers were females.
    So, let x = total number of calls made by females -------------------***
    And so, (2500 -x) = total number of calls made by males. -----------***

    "... 360 resulted in sales and were made by male callers,..."
    360/(2500-x) = percentage, in decimal, that resulted in sales from the male callers.

    "...and 480 resulted in sales were made by female callers,..."
    480/x = percentage in sales from among the female callers.

    "...If the compnay gets twice as many saler per call with a women's voice then with a man's voice,..."
    Means more females were buying than males.
    So, the percentage of female sales is twice the percentage of male sales.
    480/x = 2[360/(2500 -x)]
    480/x = 720/(2500 -x)
    Cross multiply,
    480(2500 -x) = 720x
    8(2500 -x) = 12x
    2(2500 -x) = 3x
    5000 -2x = 3x
    5000 = 3x +2x
    x = 5000/5 = 1000

    Therefore, 1000 of those 2500 calls were by females. ------------answer.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Story Problem
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: December 15th 2011, 12:26 AM
  2. story problem
    Posted in the Algebra Forum
    Replies: 5
    Last Post: June 3rd 2010, 09:40 PM
  3. Story problem help...
    Posted in the Algebra Forum
    Replies: 2
    Last Post: May 9th 2009, 05:36 PM
  4. Story Problem Help please
    Posted in the Calculus Forum
    Replies: 0
    Last Post: February 23rd 2007, 12:48 AM
  5. help with story problem
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: December 8th 2006, 11:00 AM

Search Tags


/mathhelpforum @mathhelpforum