Originally Posted by

**Caturdayz** I'm not sure if it's even solvable.

"A deer jumps in front of a car. The driver immediately slams on the breaks, leaving a skid mark .020 km long. If a nearby policeman clocked the driver at a constant velocity of 50 km/hr what was the deceleration after the breaks were applied."

Now I have:

D= .020 KM

V0= 50 km/hr

V= 0

A= ?

T= ?

and as there is no T value, I'm not exactly sure how to proceed. Seeing as the velocity formula is v= v0+at.

Any help would be greatly appreciated.

Edit: Am I to assume that "immediately" means 0 seconds? If that is the case, there wouldn't be any skid marks, as he would have stopped perfectly at 0.00 seconds...