I'm not sure if it's even solvable.

"A deer jumps in front of a car. The driver immediately slams on the breaks, leaving a skid mark .020 km long. If a nearby policeman clocked the driver at a constant velocity of 50 km/hr what was the deceleration after the breaks were applied."

Now I have:

D= .020 KM
V0= 50 km/hr
V= 0
A= ?
T= ?

and as there is no T value, I'm not exactly sure how to proceed. Seeing as the velocity formula is v= v0+at.

Any help would be greatly appreciated.

Edit: Am I to assume that "immediately" means 0 seconds? If that is the case, there wouldn't be any skid marks, as he would have stopped perfectly at 0.00 seconds...

2. Originally Posted by Caturdayz
I'm not sure if it's even solvable.

"A deer jumps in front of a car. The driver immediately slams on the breaks, leaving a skid mark .020 km long. If a nearby policeman clocked the driver at a constant velocity of 50 km/hr what was the deceleration after the breaks were applied."

Now I have:

D= .020 KM
V0= 50 km/hr
V= 0
A= ?
T= ?

and as there is no T value, I'm not exactly sure how to proceed. Seeing as the velocity formula is v= v0+at.

Any help would be greatly appreciated.

Edit: Am I to assume that "immediately" means 0 seconds? If that is the case, there wouldn't be any skid marks, as he would have stopped perfectly at 0.00 seconds...
Convert everything into SI units. Then solve for A using $2aD = V^2 - V_0^2$.