# physics problem

Just calculate how long it would take for the stone to fall down 1/2 the maximum height $t = \sqrt{(2h/g)}$, where h is the height the stone falls down. Use that time to calculate how fast it would be going in the y direction by then. Then calculate $\lvert V\rvert = \sqrt{V_x^2+V_y^2}$ where $V_x = 26\cos(38)$.