Thread: Motion problem

Hi everyone,

How would I solve this please? Thanks.

Janet drove for 30 miles at 30 miles per hour and the remaining 30 miles at 60 miles per hour. What is her average rate of speed?

Originally Posted by crazirani

Hi everyone,

How would I solve this please? Thanks.

Janet drove for 30 miles at 30 miles per hour and the remaining 30 miles at 60 miles per hour. What is her average rate of speed?

I think average rate is defined with the formula,
$\displaystyle \frac{\mbox{Total Distance}}{\mbox{Time}}$

The time wasted in the first part was,
$\displaystyle \frac{30}{30}=1\mbox{ hour}$
The time wasted in the second part was,
$\displaystyle \frac{30}{60}=.5\mbox{ hours }$

The total distance was,
$\displaystyle 30+30=60$
You add the zeros and then you add 3+3=6.


Thus, the average speed was,
$\displaystyle \frac{60}{1.5}=\frac{60}{\frac{3}{2}}=\frac{60}{1} \cdot \frac{2}{3}=40$ miles per hour.

Thank you very much.

Originally Posted by crazirani

Hi everyone,

How would I solve this please? Thanks.

Janet drove for 30 miles at 30 miles per hour and the remaining 30 miles at 60 miles per hour. What is her average rate of speed?

Average speed=(total distance)/(total time)

30 miles at 30 miles per hour took 1 hour,
30 miles at 60 miles per hour took 1/2 hour.

So average speed=(60 miles)/(1.5 hours)=40 miles per hour.

RonL

Thanks CP.

I just used another problem similar to this one. Thanks!