1. Salary Problem?

Q-> After recieving two successive raises.Harsh's Salary became equal to 15/8 times of his initial salary.By how many percent the salary was raised for the first time. If the second raise was twice as high as first?

Any help would be apprecciated.

Thanks,
Ashish

2. Hi
denote s the initial salary and r the first raise. Then
$\displaystyle s+r+2r=\frac{15}{8}s$
you get
$\displaystyle r = \frac{7}{24}s = (700/24)\%s \approx 29.2 \% s$

3. Hello, Ashish!

After recieving two successive raises, Harsh's salary became $\displaystyle \tfrac{15}{8}$ of his initial salary.
By what percent was the salary was raised for the first time,
if the second raise was twice as high as first?

Let: .$\displaystyle S$ = his original salary
And: $\displaystyle x$ = amount of the first raise.
Then: $\displaystyle 2x$ = amount of the second raise.

After the two raises, his new salary is: .$\displaystyle S + x + 2x \:=\: S + 3x$
. . And this is equal to: .$\displaystyle \frac{15}{8}S$

There is our equation . . . . $\displaystyle S + 3x \:=\:\frac{15}{8}S \quad\Rightarrow\quad 3x \:=\:\frac{7}{8}S \quad\Rightarrow\quad x \:=\:\frac{7}{24}S$

Therefore: .$\displaystyle \frac{x}{S} \:=\:\frac{7}{24} \:=\:0.291666... \;=\;29\tfrac{1}{6}\%$

Edit: Too slow . . . again!