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Math Help - Cross correlation

  1. #1
    Newbie
    Joined
    May 2009
    Posts
    21

    Cross correlation

    Hi ,

    I have [B]
    x[t_]:=[1-t]*
    P[t-0.5] and
    P[t_]:=\[Piecewise]{
    {1, Abs[t]
    0.5},
    {0, Abs[t]
    0.5}

    }
    when P represents the Rectangle Function .

    In the attached photo you can see the system .
    y[t_]:=x[t]+a*n[t];

    and I need to find the cross-corrleation integral (when a=0) of
    R_xy
    Integral : x(t+taw)*y(t)dt , between (-inf,inf)
    and because a=0 , y(t)=x(t-T0)=x(t-4) , so

    R_xy
    integral : x(t+taw)*x(t-4) , between (-inf,inf)

    But I'm having trouble finding out the limits of Taw , meaning the limits of the integral.
    hints maybe ? thanks in advance !!
    Last edited by new guy; June 29th 2009 at 02:47 AM. Reason: needed
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  2. #2
    Newbie
    Joined
    May 2009
    Posts
    21
    BTW , I'm sorry but I tried to copy paste from Mathematica so
    it would be easier to understand , but the Forum's editor wouldn't let me
    present if as it should have been .

    I've attached another photo , hopefully it would be clearer (again ,
    I'm a newbie , sorry)

    Quote Originally Posted by new guy View Post
    Hi ,

    I have
    x[t_]:=[1-t]*P[t-0.5] and
    P[t_]:=\[Piecewise]{
    {1, Abs[t]0.5},
    {0, Abs[t]0.5}

    }
    when P represents the Rectangle Function .


    In the attached photo you can see the system .
    [b]y[t_]:=x[t]+a*n[t];

    and I need to find the cross-corrleation integral (when a=0) of
    R_xy
    Integral : x(t+taw)*y(t)dt , between (-inf,inf)
    and because a=0 , y(t)=x(t-T0)=x(t-4) , so

    R_xy
    integral : x(t+taw)*x(t-4) , between (-inf,inf)

    But I'm having trouble finding out the limits of Taw , meaning the limits of the integral.
    hints maybe ? thanks in advance !!
    Last edited by new guy; June 29th 2009 at 02:46 AM.
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