this is a differential equation...and taking the inverse laplace transform it became a step function.... this is the function... y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)] thank you in advance...
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Originally Posted by thegeniusguy this is a differential equation...and taking the inverse laplace transform it became a step function.... this is the function... y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)] thank you in advance... Your text makes little to no sense, try using English and more brackets. Try: Code: > t=0:0.1:10; > y= (1/2)*[((sin(t-1)).^2/2).*(t>1)+cos(2*t)]; > plot(t,y) --> CB
> t=0:0.1:10; > y= (1/2)*[((sin(t-1)).^2/2).*(t>1)+cos(2*t)]; > plot(t,y) -->
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