this is a differential equation...and taking the inverse laplace transform it became a step function....

this is the function...

y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)]

thank you in advance...

Printable View

- Apr 23rd 2009, 01:15 PMthegeniusguyhelp me to plot this equation in Matlab....
this is a differential equation...and taking the inverse laplace transform it became a step function....

this is the function...

y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)]

thank you in advance... - Apr 23rd 2009, 10:38 PMCaptainBlack