this is a differential equation...and taking the inverse laplace transform it became a step function....

this is the function...

y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)]

thank you in advance...

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- Apr 23rd 2009, 12:15 PMthegeniusguyhelp me to plot this equation in Matlab....
this is a differential equation...and taking the inverse laplace transform it became a step function....

this is the function...

y(t) = 1/2[(sin2(t-1)u(t-1)/2)+cos(2t)]

thank you in advance... - Apr 23rd 2009, 09:38 PMCaptainBlack