θd2θ/dt2 + c/(mL)dθ/dt + (g/L)sin() = 0

c/(mL)=.5

(g/L)=2

Initial Conditions:

θ(0)=pi/2

θ'(0)=pi/2

How can this be solved in MATLAB. I am new to it and still not very good. Would ode solvers work? What other possible functions can I use? What does the code look like?