I've enclosed an excel program I made to find all different possible human dna.
I would like someone to check the work please.
note: you need to click on the green tab to get to what I want checked
I'm not asking you to check my data, what I am asking is if...
[ ( 2 ^ r ) ^ g ] ^ c
[ 2 ^ ( r • g ) ] ^ c
2 ^ ( r • g • c )
2 ^ ( 5000 • 543.4782609 • 46 )
2 ^ ( 2717391.304 • 46 )
2 ^ 125000000
( 2 ^ 1000 ) ^ 125000
( 1.0715 • 10 ^ 301 ) ^ 125000
1.0715 ^ 125000 • 10 ^ ( 301 • 125000 )
( 1.0715 ^ 1000 ) ^ 125 • 10 ^ 37625000
( 9.82144 • 10 ^ 29 ) ^ 125 • 10 ^ 37625000
9.82144 ^ 125 • 10 ^ ( 29 • 125 ) • 10 ^ 37625000
9.82144 ^ 125 • 10 ^ 3625 • 10 ^ 37625000
9.82144 ^ 125 • 10 ^ ( 3625 + 37625000 )
9.82144 ^ 125 • 10 ^ 37628625
( 9.82144 ^ 100 ) ^ 1.25 • 10 ^ 37628625
( 1.6501 • 10 ^ 99 ) ^ 1.25 • 10 ^ 37628625
1.6501 ^ 1.25 • 10 ^ ( 99 • 1.25 ) • 10 ^ 37628625
1.870199043 • 10 ^ 123.75 • 10 ^ 37628625
1.870199043 • 10 ^ ( 123.75 + 37628625 )
1.870199043 • 10 ^ 37628748.75
is correct.
in other words...
does
In otherwords is:Originally Posted by Quick
?
Is that close enough? All the arithmetic is double precision and as allCode:> >logbase(1.870199043,2)+logbase(10,2)*37628748.75 124999998.551 > >
quantities involved are positive I expect this is good to at least 10 significant
digits.
Checking this in an arbitrary precisions arithmetic package tell me all the
quoted figures above are correct (if I have typed the numerical constants
correctly)
RonL
How do you use logarithims, it seem to me that if you have something like 2^5=... than you would get rid of the two and multiply everything by log_2 and then you can use the rules of logarithims to say that log(x^y)=y*log(x), am I right? (I'm not really sure about the rules of Logarithims)Originally Posted by CaptainBlack
Another way to think of logarithms is of functions.
The function has an inverse function (I assume you know what that means).
You define that function as,
-----
An inverse function is one such as,
The interesting property between exponent and logarithms is that they express a sum as a product and a product as a sum respectively.
shouldn't it beOriginally Posted by ThePerfectHacker
you assume too much! I have been trying to figure what an inverse function is ever since I got here, I've been starting to believe that the inverse of a function is a derivative of the function, which I would like to know more about...I assume you know what that means
Originally Posted by CaptainBlack
Give a break to a high-school freshman.Originally Posted by CaptainBlack
NoOriginally Posted by Quick
When you come back I can give you an online lecture of what an inverse function is. When I was younger I also never understood it (because high schools is too informal). It makes perfect sense with setsOriginally Posted by Quick