Hi,

I was reading some notes on-line on linear multi-step methods and saw this graph:

http://i163.photobucket.com/albums/t...ion_embree.jpg
I thought it would be good MATLAB-practice to replicate the graph and gave it a go.

To start off with, I did not include Adams-Bashfort, and just used Euler's to solve the equation

. What I end up with is quite far from what i wanted, namely:

http://i163.photobucket.com/albums/t...on_mollier.jpg
Not very linear... The code that includes the loglog plot is;

Code:

`yprime = @(t,y) y; `

tspan = [0 1];

y0 = 1;

h = logspace(-3,0);

n = length(h);

absErrorEuler = zeros(n,1);

for i = 1:n

[teuler,yeuler] = euler(yprime,tspan,y0,h(i));

absErrorEuler(i) = abs(yeuler(end)-exp(1));

end

figure(2), clf,hold on

set(gca,'XDir','reverse')

loglog(h,absErrorEuler,'kd')

xlabel('h'), ylabel('error at t=1')

The implementation of Euler's is;

Code:

`function [t,y] = euler(yprime, tspan, y0, h)`

t0 = tspan(1); tfinal = tspan(end);

% set up the t values at which we will approximate the solution

t=[t0:h:tfinal];

% include tfinal even if h does not evenly divide tfinal-t0

if t(end)~=tfinal, t = [t tfinal]; end

% execute Euler's method

y = [y0 zeros(length(y0),length(t)-1)];

for j=1:length(t)-1

y(:,j+1) = y(:,j) + h*feval(yprime,t(j),y(:,j));

end

Before dealing with the details of how to put

on the x and y axes, I need to deal with the fact that the plot should show a linear relationship.

Any suggestions are welcome.

Thanks.