I try to solve this equation with secant method in MATLAB.

fn=40*n^1.5-875*n+35000

my initial guess is n1=60; n2=68; I want to find root and absolute relative approximate

error at the end of each iteration. Can you help me repair my file?

This is my m-file:

Code:

`clc`

clear

n1=60;

n2=68;

tol=1e-3;

err0=3;

iter=0;

fprintf('iteration n relative approximate error\n')

while err0>=tol

iter=iter+1;

fn1=40*(n1).^1.5-875*(n1)+35000;

fn2=40*(n2).^1.5-875*(n2)+35000;

nnew=n2-fn2*((n2-n1)/(fn2-fn1));

fnnew=40*(nnew).^1.5-875*(nnew)+35000;

err(iter)=(abs((nnew-n2)/nnew))*100;

fprintf('%2d %f %f\n',iter,nnew,err(iter))

if nnew>n1

n1=nnew;

else

n2=nnew;

end

end

nnew

iter