Matlab help can't write script

Q-2e One type of candy costs 60 cents a pound while a second type costs 80 cents a pound. How many pounds of each type must be combined in order to produce 20 pounds of a mixture worth 75 cents a pound?

I got the answer though,
type 1 =x
type 2 =y
x+y=20
y=20-x

60x+80y=75(x+y)
60x+80y=75x+75y
simplify
5y=15x
sub in y=20-x
5(20-y)=15x
100-5x=15x
100=20x
x=5
plug 5 into y=20-x
y=15

Could someone help me form a matlab script?

Quote:

Originally Posted by Mathhelpz

Q-2e One type of candy costs 60 cents a pound while a second type costs 80 cents a pound. How many pounds of each type must be combined in order to produce 20 pounds of a mixture worth 75 cents a pound?

I got the answer though,
type 1 =x
type 2 =y
x+y=20
y=20-x

60x+80y=75(x+y)
60x+80y=75x+75y
simplify
5y=15x
sub in y=20-x
5(20-y)=15x
100-5x=15x
100=20x
x=5
plug 5 into y=20-x
y=15

Could someone help me form a matlab script?

You have the pair of equations:

$x+y=20$

$60x+80y=75\times 20$

or in matrix form:

$\left[ \begin{array}{cc}1&1\\60&80\end{array}\right] \left[ \begin{array}{c}x\\y \end{array} \right] =$ $\left[ \begin{array}{c}20\\1500 \end{array} \right]$

So is we set:

$<br /> \bold{x}= \left[ \begin{array}{c}x\\y \end{array} \right] <br />$

We can write:

Code:

A=[1,1;60,80]; Z=[20;1500] X=A\Z

or of you prefer:

Code:

A=[1,1;60,80]; Z=[20;1500] X=inv(A)*Z

CB

thank you very much@!