Why is Wolfram Alpha calculating this wrong:

$\displaystyle f(u)=(arcsinu)^{-1}$ then what is $\displaystyle f'(\frac{1}{\sqrt2})=$

My calculator says $\displaystyle f'(\frac{1}{\sqrt2})=-2.99547$

Why does Wolfram Alpha say -2.29 instead?

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- Dec 6th 2009, 05:02 PMKataangelDerivative using Wolfram Alpha
Why is Wolfram Alpha calculating this wrong:

$\displaystyle f(u)=(arcsinu)^{-1}$ then what is $\displaystyle f'(\frac{1}{\sqrt2})=$

My calculator says $\displaystyle f'(\frac{1}{\sqrt2})=-2.99547$

Why does Wolfram Alpha say -2.29 instead? - Jan 4th 2010, 07:06 AMskeeter
- Jan 4th 2010, 09:28 AMCaptainBlack
Please explain exactly what you think you mean by $\displaystyle f(u)=(arcsinu)^{-1}$.

Also please give the exact command string you have given Wolfram Alpha.

Attachment 14646

CB