Can any any body help me solve this equation in Matlab
-a2(b4-b2) +a+n(b-b3)+4n{(b2a/n)+b}0.5 (b2.5-1) =1
condition
For n=0
I have to find the value of “a” when b varying from [0,1] with the step of.025
Then same thing for n=1,2,3
PLEASE SEND ME THE SOLUTION ..URGENTLY HELP REQUIRED.. THANKS
That does not help.
You will not get much help from anyone if your equation cannot be understood. Learn latex. See here: http://www.mathhelpforum.com/math-he...-tutorial.html
Then re-post the equation.
Equation is a a implicit function
(a^2)*(b^4-b^2) +a+n*(b-b^3)+4*n*{(b^2*a/n)+b}^0.5 *((b^2.5)-1) =1
condition
For n=0
I have to find the value of “a” when b varying from [0,1] with the step of.025
Then same thing for n=1,2,3
PLEASE SEND ME THE SOLUTION ..URGENTLY HELP REQUIRED.. THANKS
Its a simple equation in which there are three variable.
1st case
n=0
b=0
a=?
then again i have to find out
at n=0
b=0.025
a=?
then
n=0
b=.05
a=?
so on
like this way i have to find the value of 'a' at different value of b and n