A fishing boat leaves a dock at noon and travels due west at 40 km/h. A second boat leaves the same dock 20 minutes later and travels due south at 51 km/h. At what time, to the nearest minute, will the two boats be 116 km apart?
A fishing boat leaves a dock at noon and travels due west at 40 km/h. A second boat leaves the same dock 20 minutes later and travels due south at 51 km/h. At what time, to the nearest minute, will the two boats be 116 km apart?
$\sqrt{\left(\dfrac{2t}{3}\right)^2+\left(\dfrac{5 1(t-20)}{60}\right)^2} = 116$
Solve for $t$. That will be the number of minutes past noon. Only the positive result makes sense, so 1:59 pm.