I'm abcd, a 4digit number (a > 0).

(a + b)^c + d = dcba

Go find me!

Results 1 to 7 of 7

- Jun 1st 2016, 05:11 AM #1

- Joined
- Feb 2015
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- Ottawa Ontario
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- 1,708
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- 318

- Jun 1st 2016, 05:40 AM #2

- Joined
- Jun 2014
- From
- NJ
- Posts
- 264
- Thanks
- 91

- Jun 1st 2016, 06:02 AM #3

- Joined
- Feb 2015
- From
- Ottawa Ontario
- Posts
- 1,708
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- 318

- Jun 1st 2016, 10:27 AM #4

- Joined
- Dec 2013
- From
- Colombia
- Posts
- 1,840
- Thanks
- 592

- Jun 1st 2016, 12:37 PM #5

- Joined
- Feb 2015
- From
- Ottawa Ontario
- Posts
- 1,708
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- 318

- Jun 1st 2016, 12:55 PM #6

- Joined
- Dec 2013
- From
- Colombia
- Posts
- 1,840
- Thanks
- 592

- Jun 1st 2016, 01:50 PM #7

- Joined
- Feb 2015
- From
- Ottawa Ontario
- Posts
- 1,708
- Thanks
- 318