For the function that takes Number 1 -> Result 1, the following quartic equation works:
.
I don't have time to find quartics for the other two sets of numbers.
I'm not sure if this is the correct forum for this problem, but I am puzzled by this. I'm not the best with maths so I don't know how to solve this.
There are three numbers (below) that make three results (also below). Thing is I don't know if the 3rd number is required or not. There is a formula for each of the results. I know there is a formula for the result (each result 1 has the same formula, each result 2 has the same formula and each result 3 has the same formula), but I don't know if there is any other hidden variables to it or not. All I have figured out is that Number 2 is 25 times the value of number 1. Can anyone solve this with the information here?
Number 1: 76
Number 2: 1900
Number 3: 152
Result 1: 95.4
Result 2: 31.4
Result 3: 24.8
Number 1: 106
Number 2: 2650
Number 3: 212
Result 1: 192
Result 2: 63.3
Result 3: 49.8
Number 1: 112
Number 2: 2800
Number 3: 224
Result 1: 221.7
Result 2: 73.2
Result 3: 57.6
Number 1: 132
Number 2: 3300
Number 3: 264
Result 1: 361.5
Result 2: 119.2
Result 3: 93.8
I think you misunderstood my question (or I didn't clarify myself). Number 1 2 and (possibly) 3 are used to make result 1 and another formula to make result 2 and another one to make result 3
Call number 1 x, number 2 y, number 3 z
As you have pointed out already
i.e.
Similarly
i.e.
If you had an equation like: you could use what you know about z and y to change this into
Which simplifies to
So whatever the formula is you can always simplify it so that it only depends on Number 1
The formula for result 1 is not simple. Approximately
There is some error because I used a computer which gave the answer as a rounded decimal instead of an exact fraction.