1. ## Race problem

A can beat B by 20 yards in a race of 200 yards. B can beat C by 10 yards in a race of 250 yards. By how many yards can A beat C in a race of 100 yards?

2. ## Re: Race problem

Hello, hisajesh!

A can beat B by 20 yards in a 200-yard race.
B can beat C by 10 yards in a 250-yard race.
By how many yards can A beat C in a 100-yard race?

Let $\displaystyle \begin{Bmatrix}a &=& \text{A's speed} \\ b &=& \text{B's speed} \\ c &=& \text{C's speed} \end{Bmatrix}$

In the time A has run 200 yards, B has run only 180 yards.
B's speed is $\displaystyle \tfrac{180}{200} = \tfrac{9}{10}$ of A's speed: .$\displaystyle b = \tfrac{9}{10}a$ .[1]

In the time B gas run 250 yards, C has run only 240 yards.
C's speed is $\displaystyle \tfrac{240}{250} = \tfrac{24}{25}$ of B's speed: .$\displaystyle c = \tfrac{24}{25}b$ .[2]

Substitute [1] into [2]: .$\displaystyle c \:=\:\tfrac{24}{25}(\tfrac{9}{10}a) \quad\Rightarrow\quad c \:=\:\tfrac{108}{125}a$
. . That is, C's speed is $\displaystyle \tfrac{108} {125}$ of A's speed.

When A has run 100 yards, C has run only $\displaystyle \tfrac{108} {125}(100) \:=\:86.4$ yards.

Therefore, A wins by $\displaystyle 13.6$ yards.

3. ## Re: Race problem

@Soroban: Thanks for the detailed explanation!