# Race problem

• Nov 13th 2012, 07:26 PM
hisajesh
Race problem
A can beat B by 20 yards in a race of 200 yards. B can beat C by 10 yards in a race of 250 yards. By how many yards can A beat C in a race of 100 yards?
• Nov 13th 2012, 08:27 PM
Soroban
Re: Race problem
Hello, hisajesh!

Quote:

A can beat B by 20 yards in a 200-yard race.
B can beat C by 10 yards in a 250-yard race.
By how many yards can A beat C in a 100-yard race?

Let $\begin{Bmatrix}a &=& \text{A's speed} \\ b &=& \text{B's speed} \\ c &=& \text{C's speed} \end{Bmatrix}$

In the time A has run 200 yards, B has run only 180 yards.
B's speed is $\tfrac{180}{200} = \tfrac{9}{10}$ of A's speed: . $b = \tfrac{9}{10}a$ .[1]

In the time B gas run 250 yards, C has run only 240 yards.
C's speed is $\tfrac{240}{250} = \tfrac{24}{25}$ of B's speed: . $c = \tfrac{24}{25}b$ .[2]

Substitute [1] into [2]: . $c \:=\:\tfrac{24}{25}(\tfrac{9}{10}a) \quad\Rightarrow\quad c \:=\:\tfrac{108}{125}a$
. . That is, C's speed is $\tfrac{108} {125}$ of A's speed.

When A has run 100 yards, C has run only $\tfrac{108} {125}(100) \:=\:86.4$ yards.

Therefore, A wins by $13.6$ yards.
• Nov 17th 2012, 07:16 PM
hisajesh
Re: Race problem
@Soroban: Thanks for the detailed explanation!