A hare pursued by a hound is 50 of her own leaps before him. When the hare takes 4 leaps, the hound takes 3. In one leap, the hare goes 1.75 metres and the hound 2.75 metres. In how many leaps will the hound overtakes the hare?
A hare pursued by a hound is 50 of her own leaps before him. When the hare takes 4 leaps, the hound takes 3. In one leap, the hare goes 1.75 metres and the hound 2.75 metres. In how many leaps will the hound overtakes the hare?
Hey, I will try to answer, so here it goes:
Hare is 50 leaps of her own before hound so lets take her initial position 50*1.75= 87.5 Meters
Now it is said that Hare takes 4 leaps and the hound takes 3 therefore 87.5 + 4(1.75)x=3(2.75)x
solve the above equation and you should get x=87.5/1.25