Results 1 to 2 of 2

Math Help - This is a historical and challenging problem

  1. #1
    Newbie
    Joined
    Sep 2012
    From
    Columbus
    Posts
    14

    This is a historical and challenging problem

    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member Chokfull's Avatar
    Joined
    May 2009
    From
    Neverland
    Posts
    108
    Thanks
    1

    Re: This is a historical and challenging problem

    \sum_{i=1}^n [floor(\frac{i*m}{n})-floor(\frac{(i-1)*m}{n})+1]

    Floor(x) means the greatest integer less than or equal to x.

    Would this formula work, or are you looking for something simpler? Because this is all I could come up with.

    You can see how I got this if you look at how many squares you intersect when you go to the left 1 unit. If we let X equal the slope, then floor(x)+1 is the number of squares intersected across the first column. The same basic rule would apply for subsequent columns, but you must subtract the amount intersected in the previous columns.
    Last edited by Chokfull; October 7th 2012 at 08:50 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 0
    Last Post: September 6th 2012, 08:25 AM
  2. Replies: 8
    Last Post: September 21st 2011, 08:18 AM
  3. Challenging Problem
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: August 15th 2009, 09:53 AM
  4. Challenging problem
    Posted in the Differential Equations Forum
    Replies: 4
    Last Post: July 13th 2009, 05:49 AM
  5. Historical simulation of value at risk
    Posted in the Business Math Forum
    Replies: 2
    Last Post: November 29th 2007, 06:42 AM

Search Tags


/mathhelpforum @mathhelpforum