>_< These unknown exponents are really screwing with my head, I can't seem to get it expanded correctly.
I'm going to attempt biffboy's method to see if I can get it to work that way.
Btw, I graphed both sides out and they it the x-axis at 1; but it doesn't show the other values that way either. :/
Thank you both for the help and advice so far. Much appreciated.
therefore,
I then expanded the right side
So I have to set it to 0 so I have to subtract and getting:
and then I factor out
I did the following and got your same answers, but don't I have to use logarithms?
problem I am having is if
I assume I resubstitute the originals back in?
Should I be using Logarithm's to solve these when they get to the form or am I to just figure it out since its a simple guess?
This is correct now. You will get the right answers if you use logs but it is not necessary if you can see the answer without using them, as in 2^x=4 and 6^x=6.
For 4^x=2 we see that 2 is the square root of 4 so x=1/2. Alternatively log(4^x)=log2 so xlog4=log2 so x= log2/log4= 0.5