Thread: enlighten me please!!

If you use the first four squares to set up a system of equations with the outer numbers as coefficents of 4 unknowns and the middle numbers as the RHS constant terms you can solve the system. Use this result find the value for 'a' missing number. I get -14.8421.

I doubt this is what the author is looking for.

Thanks for looking at it, I never thought of using this method. but your right, the authors are probably looking for a constant with no decimal places. By the way this puzzle was ment for 12 year olds!!

The answer is 4!

Originally Posted by katlego

The answer is 4!

How did you get the answer 4?

I used the first square to get the last square.
14-3=11
14-5=9
14-8= 6
14-10=4

well that dose look pretty convincing, thanks a bunch dude!

I will be very disappointed if my answer is correct.