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- Apr 26th 2012, 10:27 AMjohnholden1enlighten me please!!
- Apr 26th 2012, 07:09 PMpickslidesRe: enlighten me please!!
If you use the first four squares to set up a system of equations with the outer numbers as coefficents of 4 unknowns and the middle numbers as the RHS constant terms you can solve the system. Use this result find the value for 'a' missing number. I get -14.8421.

I doubt this is what the author is looking for. - Apr 27th 2012, 02:58 AMjohnholden1Re: enlighten me please!!
Thanks for looking at it, I never thought of using this method. but your right, the authors are probably looking for a constant with no decimal places. By the way this puzzle was ment for 12 year olds!!

- May 4th 2012, 07:28 AMkatlegoRe: enlighten me please!!
The answer is 4!

- May 4th 2012, 08:35 AMfuzzyheadRe: enlighten me please!!
- May 7th 2012, 02:55 AMkatlegoRe: enlighten me please!!
I used the first square to get the last square.

14-3=11

14-5=9

14-8= 6

14-10=4 - May 7th 2012, 03:02 AMjohnholden1Re: enlighten me please!!
well that dose look pretty convincing, thanks a bunch dude!

- May 7th 2012, 11:14 PMkatlegoRe: enlighten me please!!
I will be very disappointed if my answer is correct.