# enlighten me please!!

• Apr 26th 2012, 09:27 AM
johnholden1
• Apr 26th 2012, 06:09 PM
pickslides
Re: enlighten me please!!
If you use the first four squares to set up a system of equations with the outer numbers as coefficents of 4 unknowns and the middle numbers as the RHS constant terms you can solve the system. Use this result find the value for 'a' missing number. I get -14.8421.

I doubt this is what the author is looking for.
• Apr 27th 2012, 01:58 AM
johnholden1
Re: enlighten me please!!
Thanks for looking at it, I never thought of using this method. but your right, the authors are probably looking for a constant with no decimal places. By the way this puzzle was ment for 12 year olds!!
• May 4th 2012, 06:28 AM
katlego
Re: enlighten me please!!
The answer is 4!
• May 4th 2012, 07:35 AM
Re: enlighten me please!!
Quote:

Originally Posted by katlego
The answer is 4!

How did you get the answer 4?
• May 7th 2012, 01:55 AM
katlego
Re: enlighten me please!!
I used the first square to get the last square.
14-3=11
14-5=9
14-8= 6
14-10=4
• May 7th 2012, 02:02 AM
johnholden1
Re: enlighten me please!!
well that dose look pretty convincing, thanks a bunch dude!
• May 7th 2012, 10:14 PM
katlego
Re: enlighten me please!!
I will be very disappointed if my answer is correct.