Thread: Cipher using Mod

I am trying to solve a cipher using f(x) = 3x+15 (mod 26). Going in order with A=0 all the way to Z=25. So the encoding for the letter A was A -> 0 -> 3*0+15 (mod 26) = 15 -> P.

so im getting A=15=P, B=18=S, C=21=V, D=24=Y...

i was trying to cipher ' PSRUOPVU '

and im getting: IROXFIAX.

Is this right???

Hello, Aquameatwad!

That's what I got, too . . .

But you should be deciphering PSRUOPVU. The whole process is quite abstract.

Originally Posted by a tutor

But you should be deciphering PSRUOPVU. The whole process is quite abstract.

yes i meant i was trying to decipher. and its from an abstract algebra class

Well, I'll start you off.

A -> P
B -> S
S -> R
.
.
.
.
.

Abstract

Hello, Aquameatwad!

I am trying to solve a cipher using:
Going in order with all the way to

So the encoding for the letter is:
. .

So im getting : .

i was trying to decipher

We need a decipering table . . .

. .