1 Attachment(s)

I guess this is a cryptorithm?

ABC

X DE

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FGHD

CAAC

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IDBDD

[picture if text example is terrible - Attachment 22626

Im pretty far into it, but I cant put down any numbers.

Im not sure if D is 6 or no.

Heres some of the info Ive got so far:

E ≠ 1 , D ≠ 1 , and C ≠ 1

E ≠ 5 , D ≠ 5 , and C ≠ 5

I = C + 1

E*C = ?D, '?' stands for an unknown digit.

D*C = ?C

A, C, D, E, F, I cant be 0.

Thanks in notice. Taking any skype calls: heck7er

Re: I guess this is a cryptorithm?

The key to this is the line CAAC. That number must be a multiple of 11 (sum of digits in even-numbered positions = sum of digits in odd-numbered positions). Since D is obviously not a multiple of 11, it follows that ABC, and hence also IDBDD, must be multiples of 11.

Assuming that the letters A to I stand for the numbers 1 to 9 in some order, you should be able to see fairly soon that D=6. Thus the bottom line becomes I6B66, which can only be a multiple of 11 if I+B = 6 or 17. You can rule out 17 quite easily, and then you soon find the remaining values.

Re: I guess this is a cryptorithm?

Quote:

Originally Posted by

**Opalg** The key to this is the line CAAC. That number must be a multiple of 11 (sum of digits in even-numbered positions = sum of digits in odd-numbered positions). Since D is obviously not a multiple of 11, it follows that ABC, and hence also IDBDD, must be multiples of 11.

Assuming that the letters A to I stand for the numbers 1 to 9 in some order, you should be able to see fairly soon that D=6. Thus the bottom line becomes I6B66, which can only be a multiple of 11 if I+B = 6 or 17. You can rule out 17 quite easily, and then you soon find the remaining values.

Ty mate. I used your key to check, the bonus tips were very useful. Once again, thanks.