# Cute stuff

• Oct 25th 2010, 06:12 AM
Wilmer
Cute stuff
1^1 + 3^2 + 5^3 = 135
1^1 + 7^2 + 5^3 = 175

1^3 + 3^3 + 6^3 = 244
2^3 + 4^3 + 4^3 = 136
• Oct 25th 2010, 02:22 PM
wonderboy1953
Nice. You should check Posamentier's Math Charmers
• Oct 25th 2010, 10:56 PM
Wilmer
Merci, WB.

1^3 + 5^3 + 3^3 = 153

3^3 + 7^3 + 0^3 = 370

3^3 + 7^3 + 1^3 = 371

4^3 + 0^3 + 7^3 = 407

1^4 + 6^4 + 3^4 + 4^4 = 1634

8^4 + 2^4 + 0^4 + 8^4 = 8208

9^4 + 4^4 + 7^4 + 4^4 = 9474
• Oct 25th 2010, 11:41 PM
Unknown008
Nice! (Nod)
• Oct 27th 2010, 07:29 AM
Soroban

. . $\displaystyle \begin{array}{ccc} 4^5 + 1^5 + 5^5 + 0^5 &=& 4150 \\ \\ 5^5 + 4^5 + 7^5 + 4^5 + 8^5 &=& 54748 \\ \\ 9^5+2^5+7^5+2^5+7^5 &=& 92727 \end{array}$
• Oct 28th 2010, 06:55 AM
Soroban

. . $\displaystyle \begin{array}{ccc} 1^7 + 7^7 + 4^7 + 1^7 +7^7 + 2^7 + 5^7 \;\;=\;\; 1,\!741,\!725 \\ \\ 2^8 + 4^8 + 6^8 + 7^8 + 8^8 + 0^8 + 5^8 + 0^8 \;\;=\;\; 24,\!678,\!050 \\ \\ 4^{10}+6^{10}+7^{10}+9^{10}+3^{10}+ 0^{10} + 7^{10} + 7^{10} + 7^{10} + 4^{10} \;\;=\;\; 4,\!679,\!307,\!774 \\ \\ 4! + 0! + 5! + 8! + 5! \;\;=\;\; 40,\!585 \\ \\ \dfrac{3^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2}{1^2+2^2+3^2+4^2+5^2+6^2+7^2} \;\;=\;\;2 \end{array}$
• Oct 29th 2010, 04:30 PM
harish21
$\displaystyle 99,999,999 = \displaystyle{\left( 9 +\frac{9}{9}\right)^{9 -\frac{9}{9}} - \frac{9}{9}}$
• Oct 31st 2010, 06:19 AM
Wilmer
My own, fresh off the press: 4^0 - 3^3 + 7^9 - 5^6 = 4 0 3 3 7 9 5 6
• Oct 31st 2010, 06:23 AM
bandedkrait
$\displaystyle 666+6+6+6 = (6+6/6)^{(6+6+6)/6} + (6-6/6)^{(6+6+6)/6} + 6^{(6+6+6)/6}$
• Oct 31st 2010, 09:07 AM
Wilmer
Quote:

Originally Posted by bandedkrait
$\displaystyle 666+6+6+6 = (6+6/6)^{(6+6+6)/6} + (6-6/6)^{(6+6+6)/6} + 6^{(6+6+6)/6}$

BEASTily interesting!!
• Oct 31st 2010, 07:37 PM
Soroban

. . . $\displaystyle \begin{array}{c} \text{Some Beastly Identities} \\ \\ \\ 1 + 2 + 3 + 4 + 567 + 89 \\ \\ 123 + 456 + 78 + 9 \\ \\ 9 + 87 + 6 + 543 + 21 \\ \\ 1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 + 5^3 + 4^3 + 3^3 + 2^3 + 1^3 \\ \\ 2^2+3^2+5^2+7^2+11^2+13^2+17^2\\ ^{\text{(First seven primes)}} \end{array}$

• Oct 31st 2010, 09:38 PM
bandedkrait
Quote:

Originally Posted by Wilmer
BEASTily interesting!!

Haha :). Credit goes to Prof. John Barrow. It's from his popular science book, "The Constants of Nature." :)
• Nov 10th 2010, 06:48 AM
wonderboy1953
Here's my small contribution
16^3 + 50^3 + 33^3 = 165,033.
• Nov 22nd 2010, 12:05 PM
alan2
10^2*2 + 10^1*5 + 10^0*4 = 254

oh no, thats cheating isn't it.
• Nov 22nd 2010, 03:38 PM
wonderboy1953
Quote:

Originally Posted by alan2
10^2*2 + 10^1*5 + 10^0*4 = 254

oh no, thats cheating isn't it.

I think this is a consequence of the definition of the decimal system.