Put Any Mathematic sign:
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
1 1 1 = 6
Let me know the answer.. 2,3 and 6 are solved..
Hello, tilake1!
I couldn't find an elementary expression for the 8's . . .
. . $\displaystyle \begin{array}{ccc}
(1 + 1 + 1)! &=& 6 \\ \\[-3mm]
2 + 2 + 2 &=& 6 \\ \\[-3mm]
3! \times 3 \div3 &=& 6\\ \\[-3mm]
\sqrt{4}+\sqrt4+\sqrt4 &=& 6 \\ \\[-3mm]
5 + (5 \div 5) &=& 6 \\ \\[-3mm]
6 \times 6 \div 6 &=& 6 \\ \\[-3mm]
7 - (7 \div 7) &=& 6 \\ \\[-3mm]
\log_{\sqrt{\!\!\sqrt{8}}}(8\sqrt{8}) &=& 6\\ \\[-2mm]
(9 + 9) \div \sqrt9 &=& 6
\end{array}$