Put Any Mathematic sign: 2 2 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6 1 1 1 = 6 Let me know the answer.. 2,3 and 6 are solved..
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Originally Posted by tilake1 Put Any Mathematic sign: 2 2 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6 1 1 1 = 6 Let me know the answer.. 2,3 and 6 are solved.. .
Thanks...
Hello, tilake1! I couldn't find an elementary expression for the 8's . . . . .
2 other ways for the 4's: 4 + 4 - sqrt(4) = 6 and 4/.4 - 4 = 6 On the 8's; since sqrt is allowed, then cubert should be allowed: cubert(8) + cubert(8) + cubert(8) = 6
Originally Posted by Archie Meade That's cheating Archie; you're using extra numbers, 0 and 2 !!
Originally Posted by Wilmer That's cheating Archie; you're using extra numbers, 0 and 2 !! That sinks the factorial then! cos that's a multiplication by 2, written with a footprint.
which holds for all constants.
Take this Archie: (8 + 8 + 8) / CEILING(pi) = 6
Define S to be the "Sum of the digits of a number".
Originally Posted by Archie Meade Define S to be the "Sum of the digits of a number". Define . Then and this holds for all constant 's
HaHa , and
Originally Posted by Soroban . . 3 * 3 - 3 = 6 ; keep it simple!
Another for the three 1's; arrange 1st two as a V: V1 = 6
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