Thread: Canadian wild strawberries

Jack, John and CWS's
================
Canadian Wild Strawberries (CWS) are tiny but tasty.
A and B each have a jar containing 400 CWS; they decide
to have a CWS eating race; A wins, swallowing his last
CWS when B still has 23 left. Took A 13.2 seconds; burp!
Next, B takes on C, each with a jar containing 261 CWS;
B wins, C left with 117 CWS (C has a bad toothache).
Jack: well, John, A took on C next
John: ya ya I'm sure he did
Jack: each had a jar containing N CWS's
John: oh boy
Jack: wanna try figure out what N is?
John: not really
Jack: here's a hint: in the 200 to 500 range, and they
both swallowed at same speed as in their 1st race
John: oh ya? (comes back with a printout)
Jack: A beat C by an integer amount
John: ya; I figured as much; need another clue
Jack: the sum of digits of the number of CWS that C had left
when A finished is equal to this number here
...and John knew.
What is the value of N?

I got as far as working out how many A and C ate per second but now I'm at a semi-standstill as I attempt to figure out how to find factors of fractions/recurring decimals.

Originally Posted by Mukilab

I got as far as working out how many A and C ate per second but now I'm at a semi-standstill as I attempt to figure out how to find factors of fractions/recurring decimals.

If you're looking for such factors, then you're doing something wrong.
We're dealing with integers.

I received a recurring decimal when finding how many strawberries A and C eat per second.

Originally Posted by Mukilab

I received a recurring decimal when finding how many strawberries A and C eat per second.

So?
The "number per second" does not matter.
What is needed is the A:C ratio; calculated from the given A:B and B:C ratios:
A / B = 400 / 377 ; B / C = 261 / 144 .... so A / C = 25 / 13 :
in other words, when A eats 25, C eats 13.

You're told range is 200 to 500; so you need to find the integer cases; there are 13:
1) 200 : 104 ; diff = 96 ; sumdigits = 15
2) 225 : 117 ; diff = 108; sumdigits = 9
....
13) 500 : 260 ; diff = 240; sumdigits = 6

thanks, I didn't think of it that way

I'll make sure in the future to consider this

SOLUTION:

Result of A:B and B:C races means A:C = 400:208.
So, as we're dealing with integers, jars must contain a
multiple of 25, since 25:13 is lowest.
There are 13 such possibilities in the 200-500 range:

Code:

             A ate   C ate   A-C  SUMDIGITS
             200     104     96     15
             225     117    108      9
             250     130    120      3***
             275     143    132      6
             300     156    144      9
             325     169    156     12
             350     182    168     15
             375     195    180      9
             400     208    192     12
             425     221    204      6
             450     234    216      9
             475     247    228     12
             500     260    240      6

***Only 3 is unique as sum of digits of the differences.
If Jack had pointed to any of other numbers, John could not have known.
So N = 250.