# Thread: It's easy to see that...

1. ## It's easy to see that...

You are given:

(1) a + b + c + d = e + f + g + h

(2) a + 2b + 3c + 4d = e + 2f + 3g + 4h

Now give me back:

(3) 4a + 3b + 2c + d = 4e + 3f + 2g + h

2. Hello, wonderboy1953!

You are given: . $\begin{array}{ccccc}(1) & a + b + c + d &=& e + f + g + h\\
(2) &a + 2b + 3c + 4d &=& e + 2f + 3g + 4h \end{array}$

Now give me back: . $(3)\;\; 4a + 3b + 2c + d \;=\; 4e + 3f + 2g + h$

Multiply [1] by 5: . $5a + 5b + 5c + 5d \;=\;5e + 5f + 5g + 5h$

. . . . . . $(a + 4a) + (2b + 3b) + (4d + d) \;=\;(e+4e) + (2f + 3f) + (3g+2g) + (4h+h)$

. . . $\underbrace{(a+2b + 3c + 4d)} + (4a \;+\; 3b \;+\; 2c \;+\; d) \;=\;\underbrace{(e+2f + 3g + 4h)} + (4e \;+\; 3f \;+\; 2g \;+\; h)$
. . . . . . . . . . . . . $\nwarrow\quad\text{These are equal}\quad\nearrow$

Therefore: . $4a + 3b + 2c + d \;=\;4e + 3f + 2g + h$

3. ## You have proven it, Soroban

Now what is needed are the numbers for a,b,c,d,e,f,g,h to complete the monograde equation that is being dot multiplied (hint: there can be more than one set of numbers to plug in).

4. Originally Posted by wonderboy1953
Now give me back:
(3) 4a + 3b + 2c + d = 4e + 3f + 2g + h
OK; giving it to you BACK:
h + g2 + f3 + e4 = d + c2 + b3 + a4 (3)

You're right...easy...

5. ## Extending my puzzle

Soroban did a wonderful job with my puzzle (and in record time). Now for my next related puzzle.

$a^n + b^n + c^n + d^n = e^n + f^n + g^n + h^n; n = 1,2,3$ (although not required, for simplicity's sake, let a through h be positive integers).

Now I also give you $a + 2^2b + 3^2c +4^2d = e + 2^2f + 3^2g + 4^2h$

Can you give me $4^2a + 3^2b + 2^2c + d = 4^2e + 3^2f + 2^2g + h?$

(I see no one as yet assigned values to the letters so check out 2,8,9,15 = 3,5,12,14; also check out 1,8,10,17 = 2,5,13,16 when you substitute for the letters in my first and second puzzles).

I'll be back next Sunday to check on your progress with my puzzles.

6. ## I do have a solution

I'm getting more familiarized with LaTex, Sigma notation, etc to compact the solution and other reasons. I hope to post it in this week.

I'll have some more puzzles down the road.

Happy New Year.