Nice try, EB . . . and a good guess, anthmoo!
Remember this is a "Quickie",
. . so there is usually a surprisingly simple solution.
I found all of them to be valuable learning experiences.
This problem has a headslapping, OMG kind of solution . . . brace yourself.
We have a pair of perpendicular walls and a pair of 4foot screens.
They could be arranged like this: Code:
*   *     
 *
 *
 *
* *
 * *
 * *
 * *
 *
Now consider four of these figures clustered about the right angle. Code:
*  *
* *  * *
* * *
*  *
  *  +  *  
*  *
* * *
* *  * *
*  *
We have an octagon with eight equal sides.
Obviously an octagon with a fixed perimeter has maximum area
. . when it is a regular octagon.
Therefore, the screens are placed like this: Code:
**
 *
 *
 *
 *
 135° *
 *
 *
 *
*
