Determine which integral is more crazy ...

and

3 or 6 ? The answer is 3 ! It is very interesting that although 6 is greater than 3 , the integral is actually easier than the other .

I suggest to try first , finally finish the rest (Evilgrin)

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- July 9th 2009, 01:10 AMsimplependulumCrazy integral
Determine which integral is more crazy ...

and

3 or 6 ? The answer is 3 ! It is very interesting that although 6 is greater than 3 , the integral is actually easier than the other .

I suggest to try first , finally finish the rest (Evilgrin) - July 9th 2009, 07:26 PMhalbard
If I were to attempt to find then I'd be crazy. I have attempted to find it, and I am crazy ... now.

Thanks a lot, simplependulum! You have determined which member is more crazy. - July 9th 2009, 08:48 PMAlephZero
Just use the vastly underrated method of Weierstrass Substitution... then both integrals are easy as pie...

- July 9th 2009, 09:46 PMsimplependulum
- July 10th 2009, 03:51 AMhalbard
Are you by chance referring to the identity

where , are the complex cube roots of , together with the substitution for which can be found when using ? No, I haven't tried it this way (;->)